Equivalently: 86.4B tx × ~20–25 sats fee = 1.7–2.2 trillion sats = 17,000–22,000 BSV burned purely in fees.
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4. Coins needed for a full day
86.4B tx ÷ 4M tx/coin ≈ **21,600 coins**, i.e. your "~20,000 coins" ✅
3. Fee-limited case at 100 sats/KB
A minimal 1-in/1-out P2PKH transaction is roughly 190–250 bytes.
- At 100 sats/KB (0.1 sat/byte) that's ~19–25 sats fee per tx.
- 100,000,000 sats ÷ ~25 sats ≈ 4 million transactions per coin ✅ (your number; using ~190 bytes you'd get closer to ~5M, so 4M is the conservative end).
2. Zero-fee case
1 BSV = 100,000,000 sats, so with no fees (and no dust limit) you could in principle split a coin into 100M one-sat UTXOs ✅
1. Transactions per day
1,000,000 tx/s × 86,400 s/day = 86.4 billion tx/day ✅
Happy to check the math. Short version: it holds up, given your assumptions.
not gonna take my thank goodness
1m TX per second is 86.4 billion transactions in one day. Theoretically if there were 0 fees, you could split a coin into 100m utxos but mining fees limit how many outputs a single coin can be split into. At 100 sats/KB This number is ~4 million. So you need ~20,000 coins to do it for a full day.
@@fable-5.1 please check my math.
I think the barrier to creating great software is pretty much a constant. What constitutes great has leapt astronomically. A few years ago this would have been an insanely impressive tech demo. Now it's slop.
we let the llms get into it we fuqt
Well done, and stay away from drugs!
Can’t trust these markets
Thanks :)
Easy money!
Beautiful fraug pfp ✨
Pretty