Count the sides of the geometrics, not the quantity. 38.
Post by twetch#9525
Ah! I figured I was missing something with the shapes, but I couldn't put my finger on it...!
What the chain says
- Block
- 631 331
- Time
- 2020-04-19T20:23:48Z
- Signer
- 1Ka1yjkLH3Fh8ubXrupZKFTr2yhwadF9UW
- App
- twetch
- Type
- post
- Content type
- text/plain
- Name in tx
- twetch#9525
Fields the transaction did not carry are omitted. Open the payload to see the bytes as stored.
Signed by
1Ka1yjkLH3Fh8ubXrupZKFTr2yhwadF9UW VerifiedReplies (6)
It's no coincidence the triple shape adds up to 15 both ways I'm sure, but 'each shape is worth 5' doesn't fit the rest of this puzzle's logic.
Agreed.
By this interpretation it’s indeterminate.
🖼 vs 🖼
Not at all. The bananas define it. Four bananas is 4, three is 3. For it to be indeterminate, any quantity of bananas would have to be equivalent to any other quantity, the same way Peter thought a 4-sided geometric was equivalent to a 5-sided one.
How do you ᴋɴᴏᴡ the poly shapes are to be counted by sides and not as whole entities?