Post by twetch#16755

1BuEyT…aApC Key · twetch
twetch_twembed1587156263469.jpg
What the chain says
Block
631 025
Time
2020-04-17T20:53:09Z
Signer
1BuEyTUXXXJruvGsQJwY99KnD3CVMdaApC
App
twetch
Type
post
Content type
image/jpeg
Filename
twetch_twembed1587156263469.jpg
Name in tx
twetch#16755

Fields the transaction did not carry are omitted. Open the payload to see the bytes as stored.

Signed by 1BuEyTUXXXJruvGsQJwY99KnD3CVMdaApC Verified

Reposted by (1)

Replies (14)

13L1YF…vunt Key · twetch
Replying to@1BuEyT…aApC

67👈🏻🔥😎🤷🏻‍♂️

1Ka1yj…F9UW Key · twetch
Replying to@13L1YF…vunt

I get 35.

Shapes are worth 5 each (15 for all 3)
Bananas are 1 each (4 for a group of 4)
Clock is 1 per hour on clock (3 with 3 o'clock showing)

So:
(2 o'clock) + (3 bananas) + [(3 bananas) x (2 shapes)]
= 2 + 3 + [3 x 10]
= 2 + 3 + 30
= 35

13L1YF…vunt Key · twetch
Replying to@1Ka1yj…F9UW

She's just 🤬 with us dude😂👈🏻
Different time zone in the question 🧐🤔
🤦🏻‍♂️🤷🏻‍♂️👈🏻
Maybe we need more Einsteins😆

13L1YF…vunt Key · twetch
Replying to@1Ka1yj…F9UW

She's just 🤬 with us dude😂👈🏻
Different time zone in the question 🧐🤔
🤦🏻‍♂️🤷🏻‍♂️👈🏻
Maybe we need more Einsteins😆

1Lvw3r…4c2Y Key · twetch
Replying to@13L1YF…vunt

I think yall missing the point

1EZKvw…X3oL Key · twetch
Replying to@1Ka1yj…F9UW

Count the sides of the geometrics, not the quantity. 38.

1Ka1yj…F9UW Key · twetch
Replying to@1EZKvw…X3oL

Ah! I figured I was missing something with the shapes, but I couldn't put my finger on it...!

Continue thread →
14vw4z…uU2t Key · twetch
Replying to@1Ka1yj…F9UW

I disagree. Bananas are worth 1 each & hour on clock dictates clock’s value. It’s an assumption that each shape is worth 5 yet there is no basis to assume all shapes equal. More logical would be to assign each side of each shape a value of 1.
2+3+3x11=38